Who is good at math?
Posted: Mon Jun 14, 2010 4:01 pm
I need help stat.
Like, for real.
Anyone.
Please?
Xfire me @ 'magyk'
Like, for real.
Anyone.
Please?
Xfire me @ 'magyk'
Page 1 of 9
Re: Who is good at math?
Posted: Mon Jun 14, 2010 4:07 pm
Just post what you need help with.
Re: Who is good at math?
Posted: Mon Jun 14, 2010 4:20 pm
Rational Expressions...and lots of them.
There's that for starters.
Oh, and believe me - I know that's probably "easy" and I'm retarded for not knowing how to do it, but I got stuck with the football/wrestling coach as a teacher this semester... you know, the guy who can't teach worth shit, and has "better things to do" than teach his class? That guy.
There's that for starters.
Oh, and believe me - I know that's probably "easy" and I'm retarded for not knowing how to do it, but I got stuck with the football/wrestling coach as a teacher this semester... you know, the guy who can't teach worth shit, and has "better things to do" than teach his class? That guy.
Re: Who is good at math?
Posted: Mon Jun 14, 2010 4:40 pm
The answer is C.
2y/(x*y^2) - 3x/(x^2*y^2) = 2y/(x*y^2) - 3/(x*y^2)
= (2y - 3)/(x*y^2)
Just divide the 3x by the x underneath so it becomes 3/(x*y^2), and group the numerators of both fractions as the denominators are now both equal to x times by y^2.
Edit: Removed an error, said x multiplied by x times by y^2... (tired).
2y/(x*y^2) - 3x/(x^2*y^2) = 2y/(x*y^2) - 3/(x*y^2)
= (2y - 3)/(x*y^2)
Just divide the 3x by the x underneath so it becomes 3/(x*y^2), and group the numerators of both fractions as the denominators are now both equal to x times by y^2.
Edit: Removed an error, said x multiplied by x times by y^2... (tired).
Re: Who is good at math?
Posted: Mon Jun 14, 2010 4:46 pm
Alright, that makes sense..
For this one I got A
Is that right?
For this one I got A
Is that right?
Re: Who is good at math?
Posted: Mon Jun 14, 2010 4:49 pm
Multiply the 3t^2/5 by 3/3 (as 3/3 is 1, you aren't changing the fraction), so that it becomes 9t^2/15 and the denominators now match.
So now it just becomes a matter of subtraction of the numerators as both the denominators are equal to 15:
(9t^2-4t^2)/15 = 5t^2/15 = t^2/5
Thus the answer is A.
And yea, you're right with the ninja edit.
So now it just becomes a matter of subtraction of the numerators as both the denominators are equal to 15:
(9t^2-4t^2)/15 = 5t^2/15 = t^2/5
Thus the answer is A.
And yea, you're right with the ninja edit.
Re: Who is good at math?
Posted: Mon Jun 14, 2010 4:53 pm
LCD is 15, so multiplying the first term by 3/3, you have
9t^2/15 - 4t^2/15
Factor out a common term of 1/15 to make things more clear:
(9t^2 - 4t^2) / 15
And then combine like terms in the parentheses to get
5t^2/15 = t^2/5. The answer is A.
ps: fu raptor :<
9t^2/15 - 4t^2/15
Factor out a common term of 1/15 to make things more clear:
(9t^2 - 4t^2) / 15
And then combine like terms in the parentheses to get
5t^2/15 = t^2/5. The answer is A.
ps: fu raptor :<
Re: Who is good at math?
Posted: Mon Jun 14, 2010 4:54 pm
Hah, he's getting gangbanged with math. 
I added you to xfire btw, Magyk. But I feel that you have what you need to make this reasonably easier.
These usually look intimidating but they are almost always fairly easy.
I added you to xfire btw, Magyk. But I feel that you have what you need to make this reasonably easier.
These usually look intimidating but they are almost always fairly easy.
Re: Who is good at math?
Posted: Mon Jun 14, 2010 5:11 pm
Alright.. so I did a few more, and I think I have some of this rational expressions stuff under my belt, but this problem is stumping me.
It must be either A or C right? Because the denominator will have Csquared?
Edit: I came out with A after a few trials.. would that be correct?
It must be either A or C right? Because the denominator will have Csquared?
Edit: I came out with A after a few trials.. would that be correct?
Re: Who is good at math?
Posted: Mon Jun 14, 2010 6:05 pm
Sorry, I knew this stuff, then forgot it after my finals when I realized it would not be useful to me later in life.